Optimal. Leaf size=136 \[ \frac{d^2 \sqrt{\sin (2 a+2 b x)} \sec (a+b x) F\left (\left .a+b x-\frac{\pi }{4}\right |2\right )}{24 b \sqrt{d \tan (a+b x)}}-\frac{d \cos ^5(a+b x) \sqrt{d \tan (a+b x)}}{5 b}+\frac{d \cos ^3(a+b x) \sqrt{d \tan (a+b x)}}{30 b}+\frac{d \cos (a+b x) \sqrt{d \tan (a+b x)}}{12 b} \]
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Rubi [A] time = 0.174181, antiderivative size = 136, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.238, Rules used = {2610, 2612, 2614, 2573, 2641} \[ \frac{d^2 \sqrt{\sin (2 a+2 b x)} \sec (a+b x) F\left (\left .a+b x-\frac{\pi }{4}\right |2\right )}{24 b \sqrt{d \tan (a+b x)}}-\frac{d \cos ^5(a+b x) \sqrt{d \tan (a+b x)}}{5 b}+\frac{d \cos ^3(a+b x) \sqrt{d \tan (a+b x)}}{30 b}+\frac{d \cos (a+b x) \sqrt{d \tan (a+b x)}}{12 b} \]
Antiderivative was successfully verified.
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Rule 2610
Rule 2612
Rule 2614
Rule 2573
Rule 2641
Rubi steps
\begin{align*} \int \cos ^5(a+b x) (d \tan (a+b x))^{3/2} \, dx &=-\frac{d \cos ^5(a+b x) \sqrt{d \tan (a+b x)}}{5 b}+\frac{1}{10} d^2 \int \frac{\cos ^3(a+b x)}{\sqrt{d \tan (a+b x)}} \, dx\\ &=\frac{d \cos ^3(a+b x) \sqrt{d \tan (a+b x)}}{30 b}-\frac{d \cos ^5(a+b x) \sqrt{d \tan (a+b x)}}{5 b}+\frac{1}{12} d^2 \int \frac{\cos (a+b x)}{\sqrt{d \tan (a+b x)}} \, dx\\ &=\frac{d \cos (a+b x) \sqrt{d \tan (a+b x)}}{12 b}+\frac{d \cos ^3(a+b x) \sqrt{d \tan (a+b x)}}{30 b}-\frac{d \cos ^5(a+b x) \sqrt{d \tan (a+b x)}}{5 b}+\frac{1}{24} d^2 \int \frac{\sec (a+b x)}{\sqrt{d \tan (a+b x)}} \, dx\\ &=\frac{d \cos (a+b x) \sqrt{d \tan (a+b x)}}{12 b}+\frac{d \cos ^3(a+b x) \sqrt{d \tan (a+b x)}}{30 b}-\frac{d \cos ^5(a+b x) \sqrt{d \tan (a+b x)}}{5 b}+\frac{\left (d^2 \sqrt{\sin (a+b x)}\right ) \int \frac{1}{\sqrt{\cos (a+b x)} \sqrt{\sin (a+b x)}} \, dx}{24 \sqrt{\cos (a+b x)} \sqrt{d \tan (a+b x)}}\\ &=\frac{d \cos (a+b x) \sqrt{d \tan (a+b x)}}{12 b}+\frac{d \cos ^3(a+b x) \sqrt{d \tan (a+b x)}}{30 b}-\frac{d \cos ^5(a+b x) \sqrt{d \tan (a+b x)}}{5 b}+\frac{\left (d^2 \sec (a+b x) \sqrt{\sin (2 a+2 b x)}\right ) \int \frac{1}{\sqrt{\sin (2 a+2 b x)}} \, dx}{24 \sqrt{d \tan (a+b x)}}\\ &=\frac{d^2 F\left (\left .a-\frac{\pi }{4}+b x\right |2\right ) \sec (a+b x) \sqrt{\sin (2 a+2 b x)}}{24 b \sqrt{d \tan (a+b x)}}+\frac{d \cos (a+b x) \sqrt{d \tan (a+b x)}}{12 b}+\frac{d \cos ^3(a+b x) \sqrt{d \tan (a+b x)}}{30 b}-\frac{d \cos ^5(a+b x) \sqrt{d \tan (a+b x)}}{5 b}\\ \end{align*}
Mathematica [C] time = 2.38904, size = 131, normalized size = 0.96 \[ \frac{\cos (2 (a+b x)) \csc (a+b x) (d \tan (a+b x))^{3/2} \left ((10 \cos (2 (a+b x))+3 \cos (4 (a+b x))-3) \sqrt{\tan (a+b x)}+10 \sqrt [4]{-1} \sqrt{\sec ^2(a+b x)} F\left (\left .i \sinh ^{-1}\left (\sqrt [4]{-1} \sqrt{\tan (a+b x)}\right )\right |-1\right )\right )}{120 b \sqrt{\tan (a+b x)} \left (\tan ^2(a+b x)-1\right )} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.16, size = 250, normalized size = 1.8 \begin{align*} -{\frac{\sqrt{2} \left ( \cos \left ( bx+a \right ) -1 \right ) \cos \left ( bx+a \right ) \left ( \cos \left ( bx+a \right ) +1 \right ) ^{2}}{120\,b \left ( \sin \left ( bx+a \right ) \right ) ^{5}} \left ( 12\, \left ( \cos \left ( bx+a \right ) \right ) ^{6}\sqrt{2}-12\,\sqrt{2} \left ( \cos \left ( bx+a \right ) \right ) ^{5}-2\, \left ( \cos \left ( bx+a \right ) \right ) ^{4}\sqrt{2}+5\,\sin \left ( bx+a \right ){\it EllipticF} \left ( \sqrt{-{\frac{\cos \left ( bx+a \right ) -1-\sin \left ( bx+a \right ) }{\sin \left ( bx+a \right ) }}},1/2\,\sqrt{2} \right ) \sqrt{{\frac{\cos \left ( bx+a \right ) -1}{\sin \left ( bx+a \right ) }}}\sqrt{{\frac{\cos \left ( bx+a \right ) -1+\sin \left ( bx+a \right ) }{\sin \left ( bx+a \right ) }}}\sqrt{-{\frac{\cos \left ( bx+a \right ) -1-\sin \left ( bx+a \right ) }{\sin \left ( bx+a \right ) }}}+2\, \left ( \cos \left ( bx+a \right ) \right ) ^{3}\sqrt{2}-5\, \left ( \cos \left ( bx+a \right ) \right ) ^{2}\sqrt{2}+5\,\cos \left ( bx+a \right ) \sqrt{2} \right ) \left ({\frac{d\sin \left ( bx+a \right ) }{\cos \left ( bx+a \right ) }} \right ) ^{{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (d \tan \left (b x + a\right )\right )^{\frac{3}{2}} \cos \left (b x + a\right )^{5}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\sqrt{d \tan \left (b x + a\right )} d \cos \left (b x + a\right )^{5} \tan \left (b x + a\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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